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I'm done with this discussion as well. You have your opinion, I have mine. If I did not think there was a chance the butane fridge would work, I wouldn't bother sending for the parts to replicate it. I've been studying refrigeration and air conditioning since taking 2 years of small engine and appli...

Well Tom you said it yourself. If the answer to my question violates the laws of thermodynamics, then it is certainly outside of tradition. Well, I don't know how much more mainstream you can get than an AI Overview: Compress_20240522_105443_3860.jpg There is no issue when it comes to the first law...

This; https://physicstasks.eu/2179/work,-pressure-and-heat-of-the-air-during-isothermal-expansion Already cited and many other similar examples, online discussions regarding isothermal expansion and the conversion of heat into work seem applicable to your question. At least from a theoretical and ma...

Stroller wrote: ↑Tue May 21, 2024 5:24 am It's the action of the expanding gas "consuming" energy that I am interested in. Is internal energy really reduced when the gas expands, other than by conduction losses to the surrounding colder surfaces of the engine. And if so, how exactly? The ...

Your anticipated response is why I gave you your thread back, obviously. Kindly stay away from mine. Thank you. You claim your example, as a Stirling cycle, is "MORE relevant to thinking about DIY Stirling engines". It bears no resemblance to a Stirling cycle of any kind, theoretical or p...

Stroller wrote: ↑Wed May 22, 2024 12:41 am
.... My example is more relevant to thinking about DIY Stirling engines, ...

Your example is crap, obviously.

You asked. Sorry, if they are incongruent with yours. This is an open forum. Call my knowledge "superior" isn't helping you or me. Your knowledge and mine are equal in that our points are based on what we have learned. I as well as you and others here try to learn things from others, and ...

Apparently I need further clarification. Sorry. You are going to ridiculous, bizarre extremes to "prove" my statement that compression generates heat of compression during compression is "misleading". Just because heat is also added due to displacer motion is irrelevant to the f...

...The link you sent left out what accomplished the expansion. It states clearly: "heat supplied to the gas". Also: "work performed by the gas " Perfectly clear IMO. "Heat supplied to the gas" "work performed by the gas" Anyway, this is VincentG's question to...

Driving posters away opens the door for new posters to which your job, as educator, starts up at the beginning. As I've tried, you have identified an anomaly that bares further investigation. But it still may fit nicely into 200 year old and current theory. Your methods of discourse here suffer fro...

As you like to point out the "heat of compression" is "instantaneous" so it stops when the volume change stops. The gas is being pushed through the regenerator to the hot space at the fastest rate. Compression is zero. Delta energy from compression is zero during this period. So...

The online example says nothing about "pulling" You would only have to pull on it for the whole stroke if the buffer pressure were at or higher than P1. P2 is even lower. If the buffer pressure where lower than P2 no pulling would be necessary for the whole stroke, but a stop would be nee...

I suppose I should mention the first is energy/work out, the second requires energy/work input. The first pushes, the second must be pulled. I hope this makes sense. The online example says nothing about "pulling" Ideal gas of a volume of 1 m3 at initial pressure of 200 kPa is expanding i...

Fool wrote: ↑Tue May 21, 2024 10:52 am At TDC the piston is briefly not moving. ...

So what?

It just completed generating "heat of compression" the heat of compression is at the maximum and still there, concentrated at TDC.

Your long diatribe is irrelevant.

P1V1/T1 = P2•V2/T2 For the given parameters: P1=P2 Canceling P from both sides: V1/T1 = V2/T2 From given parameters: T2=2•T1 Inserting in to the equation: P1/T1=P2/(2•T1) Dividing both sides by (2•T1): P1•(2•T1) / T1 = P2 Cancelling T1 top and bottom and rearranging: 2•P1 = P2 Please show your &quo...