Stirlingengineforum.com

Stainless steel is pretty non-conductive to begin with, so if the SS utensil pot is mostly heated on the bottom there might not be much thermal creep to worry about up that high. I've sometimes thought with SS it might actually be a good idea to electroplate the outside with copper, like a copper bo...

... possibly using a material that would place a thermal barrier between the hot and cold ends to reduce "thermal creep". I "could" place an insulating ... I agree. Something that would form a thermal barrier would be best, for what I think should be obvious reasons. You want as...

. ... Tesla, wrote his article during a time when the second law, and Entropy were being hotly debated and still unknown to most. He probably spent the rest of his life trying to figure out that his ambient cold hole scheme can't work. He was unsuccessful in building one. Entropy and the second law...

... If Tesla, and others, are right, where are the devices? Why can't we buy them today? I could really use free energy. It's a wonder. You may have to visit the island nation of Vanuatu. Maybe someone should ask Jeff Muller what happened to his perpetual air compressor. I don't know, but it's hard...

.... It is impossible to compare fuel tank levels with internal energy levels because it is just as easy to fill the top 1/4 of a tank as the bottom 1/4, and it is harder to fill at higher temperature than zero Kelvin, it harder to compress 14.7 psi than zero psi. That is the penalty of back work a...

It seems Tesla didn't speak or write anymore publicly about his ambient heat engine after the article in 1900, but apparently kept working on it until around 1930 ? I don't know any more than what he put in that article. What seems interesting to me about compressed air is as the air is compressed t...

I think that chart is for steady state currents and temperatures and COP's. At 0.1 times Amax, it will produce 10° of delta T, at a COP of 2. At 0.2 times Amax, it will produce 20° of delta T, at a COP of .7 Very tiny amounts of power for small steady state COP's, and delta T's, max. Not sure how r...

What Jeremiah says near the begining of this video about the importance of the pump to create a vacuum in the turbine to greatly increase the efficiency of the turbine also sounds very similar to what you are proposing, using the pump as a kind of replacement for a cold condenser. https://youtu.be/h...

Personally, Paul here seems to know what he's talking about. https://youtu.be/f4UmvPLmV40 In this interview he mentions ienergysuoply (Jeremiah) as a partner he was working with, which makes me tend to think Paul may have been Jerimiah's partner that died, but whatever the case he seems to not be co...

The intro blurb in the previous video says "compressed humid air" is supply to the turbine. This is, I think, similar to this phenomenon: https://youtu.be/2hYQtB4QkEY But as Jeremiah commented, this normally requires high pressure. A shop compressor that big as in this video is probably at...

It seems this was low pressure "cold steam" driving the turbine ? The second stage turbine providing the vacuum rather than a condenser/ice bath Still, producing a 100°f drop in temperature at the turbine. It is a bit frustrating that the circumstances and actual details of this test are n...

I believe this is the double two stage turbine without any condenser or load, still, there is already ice forming within the turbine. https://youtu.be/c5NzHvGxTss This was five years ago, which seems like the more recent developments are somehow less advanced ? One of Jerimiah's comments says: . It ...

A fairly simple experiment I'd like to try when I get a turbine, which may be in a week or so, tracking says it is on the way, from China, would be this: Compress_20240602_080527_7386.jpg This would, of course, have to be a "saturated vapor with all air removed from the system. This could be ac...

My understanding at the moment, (which could be wrong, as I've only just begun looking into these things and some of the informations is contradictory or confusing) Is, what that chart indicates is when first starting up a Peltier device is at 0°∆T and it's power draw is low and it's COP is basicall...

What I object to mostly is how (added) "heat" and (existing) "internal energy" are treated as equivalent for the purposes of the "Carnot limit" equation η=(Th -Tc)/Th ⋅100% Tc is the internal energy before adding heat Th is the internal energy after adding heat Th - Tc ...