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Just reporting what you saw. Heated by a torch. Free piston getting closer to top/head, i.e., less gas cushion. Balloon not inflating because the same amount of gas is in the cylinder trapped by the balloon, but now on cold side of piston. What is there to imagine? You just wrote above: The piston ...

Sorry but using "all" of Qhz, all the "internal energy" down to absolute zero, all 100 joules added PLUS all the "given" 300 joules of "environmental heat" already inside the engine before heat was added, before the engine started, would be like 400% efficienc...

... If the cycle starts at Qcz, and DQh is added. It is then expanded doing work a maximum of Qhz Joules will be converted to work. The gas will be at T = 0 Kelvin and P=0. Now it must be compressed back to P=atmospheric an Tc=300 K. It will take 300 J to do so. That makes the machine's efficiency ...

Basically, plain and simply : n=(Qh-Qc)/Qh And : Q=Cv•M•T So : n = (Qh - Qc) / Qh n = (Cv•M•Th - Cv•M•Tc) / Cv•M•Th Simplifying : n = (Cv•M(Th-Tc) / Cv•M•Th Canceling : n = (Th-Tc) / Th If the cycle starts at Qcz, and DQh is added. It is then expanded doing work a maximum of Qhz Joules will be conv...

Begining of derivation: Taking the above 'noted' equation "Qhz = Qcz + DQh" and subtracting Qcz from both The term 'n' applies to the engine regardless of 'Qcz' base heat amount or reference point. I t will have the same efficiency burning the same energy at the same temperatures but with...

Begining of derivation: Taking the above 'noted' equation "Qhz = Qcz + DQh" and subtracting Qcz from both The term 'n' applies to the engine regardless of 'Qcz' base heat amount or reference point. It will have the same efficiency burning the same energy at the same temperatures but with ...

Tom, why would the balloon inflate? The gas heats up, expands, pushes the piston outward causing some inflation. The engine then runs. Any leakage by the piston would make the piston run closer to the closed end. The gas going by the piston would cool and return to it's original volume. Hence it wo...

But maybe gas can "stretch" like a rubber band. IDK. But I can see that the piston in a Stirling engine does infact return. Without a flywheel. Without a displacer. With no apparent "sink" or viable heat outlet. I've done the experiments myself, so I can't really just dismiss wh...

Begining of derivation: Taking the above 'noted' equation "Qhz = Qcz + DQh" and subtracting Qcz from both The term 'n' applies to the engine regardless of 'Qcz' base heat amount or reference point. It will have the same efficiency burning the same energy at the same temperatures but with ...

a2+b2=C2 would be pretty useless if it only worked for equilateral triangles. Pythagoras is spinning in his grave. :laugh: There is of course, no such thing as an equilateral right triangle. Which is the point. There is no such thing as a "perfect" Carnot engine either An algebraic formul...

Thot = 600 Tcold = 300 Qhot = 150 joules You forgot the units, 'Kelvin', for the temperatures. You put temperatures into an energy equation, and mixed them with heat. The reason it worked in the previous example is that DQh and DT were both 100. It had a one to one relationship between energy and t...

Thot = 600 Tcold = 300 Qhot = 150 joules You forgot the units, 'Kelvin', for the temperatures. You put temperatures into an energy equation, and mixed them with heat. The reason it worked in the previous example is that DQh and DT were both 100. It had a one to one relationship between energy and t...

Suppose we use my original values ? Thot = Qhz = 600 (but also 450 ?) Tcold = 300 = Qcz Qhot = 150 joules = DQh DQh = Qhz - Qhz(1-n) 150 = 600 - 600(1 - .25) 150 = 600 - 600(0.75) 150 = 600 - 450 150 = 150 Hey, worked out! But elsewhere Qcz + DQh = Qhz Qcz + DQh = Qhz 300 + 600 = 900 So Qhz can equa...

Can we try some other more "realistic" (in your opinion) values? How about Thot = 600 Tcold = 300 Qhot = 150 joules Anything wrong with those numbers? Equations are supposed to balance right? Isn't that what the equal sign is for? Isn't that what mathematical precision is all about? We ass...

2+x=4 What does x equal? X=5 2+5=4 7=4 The equation must be wrong. Give me a break. An equation isn't valid for any numbers you want to put in. An equation is only valid if use properly. It should at least be valid for the potential range of application, don't you think? Or are you presupposing ONL...