Stirlingengineforum.com

... Only during an adiabatic process does Caloric/heat not "fall"/flow,. You have described an adiabatic process. That is why it will generate zero CYCLIC work. ... No I haven't 1st convenient search reference: Isothermic reactions are characterized as reactions that occur in constant tem...

Tom, by "removing rocks" you are reducing the inside pressure. Reduced pressure on water reduces the temperature at which it boils. That is a delta T. Sorry. ... No it isn't. Reducing the boiling point only means the water boils/changes phase to a gas much more readily at 100°C it does no...

The essence of "Caloric theory" is that "the fall of Caloric" (temperature change) is the only metric and that without that there is zero work, zero efficiency. Such a view is based on obsolete, incomplete knowledge. I could, for example, envisage a "perfect" or "i...

The rocks are the load... .... The magic answer is the flywheel ... Sure. The flywheel however is only a very small part of "the load". A "reversible" part. Around 7:00 I think, Kahn mentions that the gas does work putting "potential energy" into the rocks. The potenti...

OK, well, suppose we all watch this video: https://youtu.be/aAfBSJObd6Y What is the taking away and replacing of the "pebbles" supposed to represent? This seems to be essential to the operation of the engine but in the real world people don't remove weights from the piston in their engine ...

Right, so here is your typical Carnot cycle PV diagram: Carnot_cycle_p-V_diagram.jpg Perhaps one of you guys can determine the external load or shaft work output for this PV representation and explain how you arrived at that determination or value for mechanical torque, watts generated or whatever.

Do you have the power piston finished?

Are you still using a break diaphragm?

I fist proposed the comparative engines running and not running on ice here: https://stirlingengineforum.com/viewtopic.php?p=3951 And included this illustration: tesla-test.gif One prediction of the outcome was: The experiment is worth trying, but my bet would be that the ice would melt fastest unde...

... I tend to believe that in a piston engine, heat is largely not converted to work and that it does infact flow through the engine, if work is being done. ..... After what must have been several years of reading all kinds of conflicting views and theories spanning centuries, I didn't know what to...

... ...I assume your current PV beef is that PV plots disregard load vs no load conditions. ... My "beef" is, basically; Carnot based his assumption that heat goes THROUGH a heat engine in tact, to power the engine just like water through a turbine, (that is, there is no material change i...

... Tom, I maybe wrong about how you think in regard to the following, but please hear me out. I think you are battling the following beliefs : 1: 200 years of thermodynamics and engine building are somehow wrong. 2: 2000 year old mathematics, such as Calculus and graphs, are wrong. 3: Current scie...

. .... Furthermore, if a system performs work by expanding and the temperature drops, performing work on the system by compressing it will raise the temperature back for zero work out. If the pressure starts at 1 bar and the volume doubles the pressure will drop to 0.5 bar. So atmospheric pressure ...

.... When describing these systems, it is the equation that matters. Experiments just shape the equations. Without the equations there is zero understanding. .... . That may be YOUR point of view, and your entitled to it, but Personally I think that's crazy Mathematics needs to be grounded in physi...

... If the pressure starts at 1 bar and the volume doubles the pressure will drop to 0.5 bar. So atmospheric pressure will push the piston back until the pressure equalizes. At what volume will the pressure equalize? Right back where it started. Yes , but ... But nothing. "Work" has alrea...

Internal energy remains the same because the heat input is immediately converted to work output, 100% so there is no added "heat"/energy left over to increase the "internal energy". That is only true in reference to zero Kelvin and Zero pressure. We are talking, so far about exp...