Stirlingengineforum.com

From that article I thought this was interesting. Something I haven't seen before: So for 𝑇 > 𝑇inv, an expansion at constant enthalpy increases temperature as the work done by the repulsive interactions of the gas is dominant, and so the change in kinetic energy is positive. But for 𝑇 < 𝑇inv, expans...

..., I would imagine the biggest reduction in temperature would be from expanding gas into a vacuum where the gas is able to use all it's kinetic energy to expand unrestricted. Actually it's just the opposite. When expanding into a vacuum the gas has nothing to do work against so doesn't loose ener...

the internal gas pressure is still contributing, still doing work and still actually losing internal energy so still dropping in pressure and temperature due to work output. This is the part I'm having trouble with. The working fluid can only still be doing work while it's above ambient pressure, b...

Some late night experimenting, but no great results so far. https://youtu.be/AaEfauPTqYo?si=0oBcnqy-1X2BbVqA If the flywheel assembly is removed, which can be accomplished rather quickly by just loosening the big hose clamp, the engine will run, apparently quite strongly. Put the flywheel back on an...

Only if some working fluid has been bled from the engine at working temperature near TDC. Otherwise, you're not going to get the partial vacuum at BDC needed for the ambient atmosphere to do any pushing on the return stroke. Negative. We are seeing a strong return stoke with these engines while hav...

I've been avoiding the rock analogy. But to me rolling the same rock up and down a hill seems pointless. How about we ask, if the expansion stroke rolls a rock uphill, can the return stroke roll another rock up the same hill, thus performing more useful work? Not exactly. The point is, in doing wor...

If your asking me, conversion of heat into work is a "refrigeration effect" of a sort. I'm still working out exactly what I am asking so bear with me lol. And I mean thermal efficiency. Air cools down when it expands, and heats when it's compressed. If the air cools down further than it w...

There is a good reason why these equations are turning out with the values of 100 = 400. Because according to the Carnot limit, the 100 joules of heat added is not just in some kind of RATIO. It says, mathematically that the heat supplied actually IS all the heat down to absolute zero because it tri...

I mean, we are only talking about a piston returning to TDC after being pushed "up hill" against 1 atmosphere. Similar to lifting a weight against gravity or winding a spring. If it is "harder" to lift a heavier weight, the equivalent is still stored as "potential energy&quo...

Stroller wrote: ↑Wed Apr 24, 2024 2:57 pm The further the boulder makes it up the hill on the other side of the valley, due to it's momentum; the harder it was to push it up the hill on this side of the valley, due to its inertia.

So?

I mean, in principle. If you store "potential energy" in a bolder, by rolling it up a hill, it can then roll down. I don't think this is any different then driving out a piston "up hill" against atmospheric pressure. It can then return. But what happens when the bolder reaches th...

In that case, I'd say 70 units of heat would be "rejected" to the room. The rest going out as "work" is tied up as potential energy in the lifted weight. Ok, now were getting somewhere. Now how do we tie in the theory that there is a potential lowering of gas temperature and ref...

The engine is perfectly insulated so no heat is lost other than what is exhausted or rejected to the sink. The heat is supplied to the engine within the confines of an isolated chamber so as to not heat the room directly. The only thing heating the room is what is exhausted/rejected to the sink. In...

Basically looks like the "hot" piston has been entirely replaced by a displacer, or perhaps regenerative displacer of some sort, but no longer an Alpha type piston.

.

The following is some improvements to the original post, not a direct Quote: Question: How does Qh an Qc become Q's all the way to Zero, and then, Th and Tc? Answer: . ... ...So Qhz should have the same relation ship to Qcz that DQh has to DQc, in other words, 'n' is the same. Basically this says t...