Stirlingengineforum.com

I was speaking of the change in temperature after compression had stopped.

I leave it there. And leave you alone. Sorry.

Sorry. I'll leave you alone.

Yes. Lots of fuel.

I investigated pelet making but have found the process a little too finicky and costly. I'm thinking a fluidized bed burner, perhaps.

I seem to have missed the photos Tom provided. You are gracious to give the smaller tube a foot. Perhaps, but it appears to be wrapped into a 1" circle, twice. That is about 6.3". Add a couple for the legs, gives a total of about 8". Eight to 12, "pretty darn skinny", about ...

You asked. Sorry, if they are incongruent with yours. This is an open forum. Call my knowledge "superior" isn't helping you or me. Your knowledge and mine are equal in that our points are based on what we have learned. I as well as you and others here try to learn things from others, and o...

Apparently I need further clarification. Sorry.

From the link you provided: The resultant pressure p2 of the air can be determined from the above-mentioned Boyle-Mariotte law as well p1V1=p2V2. Therefrom we express the final pressure p2=p1V1/V2=p1V1/2V1=p1/2. p2=p1V1/V2=p1V1/2V1=p1/2 Breaking it down: Dividing both sides by v2: p2=p1V1/V2 Substit...

The online example says nothing about "pulling" You would only have to pull on it for the whole stroke if the buffer pressure were at or higher than P1. P2 is even lower. If the buffer pressure where lower than P2 no pulling would be necessary for the whole stroke, but a stop would be nee...

I own a "puny" portable sawmill that has a 1950's 13000 D8 Cat motor, diesel, that runs a 5' circular saw blade. It has a two cylinder gasoline/petral "pony" motor as the starting motor. It is both electric start and hand crank. The crank works better. Not sure why. Better spark ...

As you like to point out the "heat of compression" is "instantaneous" so it stops when the volume change stops.

The gas is being pushed through the regenerator to the hot space at the fastest rate. Compression is zero. Delta energy from compression is zero during this period.

I suppose I should mention the first is energy/work out, the second requires energy/work input. The first pushes, the second must be pulled. I hope this makes sense.

Given parameters: P1=P2 Atmospheric pressure plus constant weight on top, pressure stays constant for entire expansion. T2=2•T1 300 =T1 600 = T2 600 = 2•300 The example where P2=P1/2? Is for T1=T2 and V2=2•V1 Taking the same equation: P1•V1/T1= P2•V2/T2 Since T1=T2 they cancel each other, (multiple ...

Driving posters away opens the door for new posters to which your job, as educator, starts up at the beginning. As I've tried, you have identified an anomaly that bares further investigation. But it still may fit nicely into 200 year old and current theory. Your methods of discourse here suffer from...

P1V1/T1 = P2•V2/T2

For the given parameters:
P1=P2

Canceling P from both sides:
V1/T1 = V2/T2

From given parameters:
T2=2•T1

Inserting in to the equation:
P1/T1=P2/(2•T1)

Dividing both sides by (2•T1):
P1•(2•T1) / T1 = P2

Cancelling T1 top and bottom and rearranging:
2•P1 = P2

At TDC the piston is briefly not moving. Look at the piston's position verses time plot. It is at the top of the sine wave. It moves (rough numbers) 1% for a crank moving 5%. Compression is "over" before TDC, mostly over, especially in a LTD Stirling. At the same time the displacer is movi...