Stirlingengineforum.com

In fact I'll do it again. Qh heat added from Tc to get to Th. Uh total energy contained in the gas at Th Uc total energy contained in the gas at Tc Qh=Uh-Uc 100=400-300 Heat equals the change in internal energy. Starting point one: Uc=MCvTc 300=MCv300 Maximum point two: Uh=MCvTh 400=MCv400 MCv= Mass...

Only the ratios are equivalent. Because the differences cancel.

That was shown many times over. The 45 pages of waste is from you not seeing the obvious.

Heat is never hot or cold. Internal energy can be hot or cold. Speaking only thermodynamically, of course. Heat is a description of the transfer of energy from hot to cold. Internal energy is a condition, a state, of how hot something is compared to absolute zero Kelvin. Internal energy is calculate...

The heat doesn't just jump off the bolt and head for the water on its own. Heat transfer in the air is by conduction, convection, and radiation. Which one of these are not the heat "jumping off and heading to the water"? None. For your statement to pass scientific testing, all three must ...

I also don't think that Tom will ever understand how the differences between a state variable and path variable cancel when put into a ratio, and how they are depicted on a PV diagram.

Still he tries to equate, heat a path variable with, internal energy a state variable. He just loses it every time.

Yes, I get it, but take another look at your Q=.................=U and try to justify how any path function can (ever) equal a state function ??? I said I was wrong. Good catch. I don't think Tom will ever understand how a state variable differs from a path variable. The heat doesn't just jump off ...

Tim Booth wrote:But I think we've had this conversation before. If you keep adding wood to a fire it doesn't mean wood is not being added or burned if the fire looks the same after three days.

What the fire looks like is internal energy. The wood added is heat in. The wood burnt is heat out.

Just to be clear, cooling due to transfer of kinetic energy is over and above cooling that may be due to "expansion", simply spreading out the heat over a larger volume. IMO there is no such thing as heat attempting to reach equilibrium. The idea that heat wants to combine with cold, seek...

(Fool, no help please) Apparently Fool is no help. LOL. I keep thinking about the old saying that has a horse and water. We need more mathematicians. I get it, but doubt anyone else here does... I keep thinking about Feynman's method of making people think by leaving errors in textbooks. And how mu...

If that were the case, I think the universe would have reached equilibrium eons ago. Ha ha stay on subject, Stirling Engines. The universe is way larger than our little puny, understatement, Stirling Engines, and probably takes way more time to cool. In fact the big explosion has cooled to 3 Kelvin...

Hot gas doesn't contain heat any more than it contains work when compressed.

And Tom, I don't see any evidence that heat will not flow as fast as it can to reach equilibrium, depending on the resistance of the medium it has to work with. Heat a nut or bolt up to red hot. Feel the heat rushing out of the metal to your colder hand. See how long you can hold a nut that is a wa...

gases have a temperature. Temperature is manifest by kinetic energy. Contained Kinetic energy is stored energy. It is not heat. It is not work. It is called internal energy. A spinning flywheel doesn't have work in it, it has stored kinetic energy, internal energy. Work is just how it got there, or ...

"See what I mean?" At least I was adding some science too, a point you didn't address choosing instead to just squabble. What kind of a comment would you consider yours? Sarcasm, taunting, gloating? Squabbling... Rhetorical questions are questions where the obvious answer is meant to demon...

.... The equation: n = (Qh-Qc)/Qh Could be rewritten: n = (Uh-Uc)/Uh Which has nothing to do with heat, only the currently contained internal energy when at the hottest and coldest. For a full cycle: But Tom is assuming it is written: n = (∆Qh-∆Qc)/∆Qh .... Tom likes to equate an energy river to an...