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.... The equation: n = (Qh-Qc)/Qh Could be rewritten: n = (Uh-Uc)/Uh Which has nothing to do with heat, only the currently contained internal energy when at the hottest and coldest. For a full cycle: But Tom is assuming it is written: n = (∆Qh-∆Qc)/∆Qh .... Tom likes to equate an energy river to an...

Just because you don't understand it, doesn't make it meaningless. Seems like something you've said in the past, about refrigerators. If you want to eliminate squabbling, you probably don't want to enter any discussions. Do you consider a bank balance the same as dollars in? Do you consider a bank b...

"The idea that heat wants to combine with cold, seeks out or finds itself compelled to flow to cold is just Caloric/Carnot theory mythology." Energy has nowhere to go but away from itself. Away from itself is the cold, or cooler. Energy will only stay separated if there are forces keeping ...

But the gas expanding (pressure) is just gas molecules striking the piston, transferring kinetic energy to the piston, loosing kinetic energy in the process. This is true. You seem to also, at the same time, conveniently ignore the rest of the cycle, specifically the return stroke. During the retur...

Temperature equates to internal energy through the following equation: Q=M•Cv•T=U Heat is: ∆Q=M•Cv•∆T not equal to U The equation: n = (Qh-Qc)/Qh Could be rewritten: n = (Uh-Uc)/Uh Which has nothing to do with heat, only the currently contained internal energy when at the hottest and coldest. For a ...

The work of lifting the rocks has been accomplished and GPE created without the consumption or transformation of the original thermal energy. The room temperature will only be slightly cooler than if the hot and cold conducted, depending on how massive the room is compared with the stored energy in...

VincentG, you already know the following, so it is just for collaboration. The first law of thermodynamics, conservation of energy, and the constraints of a complete cycle lead to the following equation: W=Qh-Qc This literally and mathematically.means that if work is performed by a device/engine, th...

Again, I go back to my very simple question of does the isolated room reach 0k if all the rocks are lifted. Any possible method can be used inside the room to lift the rocks. There are no limitations, let your imagination run wild. You are still limited by nature. Wild thinking can help by viewing ...

I was speaking of the change in temperature after compression had stopped.

I leave it there. And leave you alone. Sorry.

Sorry. I'll leave you alone.

Yes. Lots of fuel.

I investigated pelet making but have found the process a little too finicky and costly. I'm thinking a fluidized bed burner, perhaps.

I seem to have missed the photos Tom provided. You are gracious to give the smaller tube a foot. Perhaps, but it appears to be wrapped into a 1" circle, twice. That is about 6.3". Add a couple for the legs, gives a total of about 8". Eight to 12, "pretty darn skinny", about ...

You asked. Sorry, if they are incongruent with yours. This is an open forum. Call my knowledge "superior" isn't helping you or me. Your knowledge and mine are equal in that our points are based on what we have learned. I as well as you and others here try to learn things from others, and o...

Apparently I need further clarification. Sorry.

From the link you provided: The resultant pressure p2 of the air can be determined from the above-mentioned Boyle-Mariotte law as well p1V1=p2V2. Therefrom we express the final pressure p2=p1V1/V2=p1V1/2V1=p1/2. p2=p1V1/V2=p1V1/2V1=p1/2 Breaking it down: Dividing both sides by v2: p2=p1V1/V2 Substit...